In reply to First post

Re: Weekly Discussion

by Al Amin 193-15-2981 - Saturday, 27 June 2020, 8:14 PM

(x-1)/2

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In reply to Al Amin 193-15-2981

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:44 AM

Correct!!!

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Re: Weekly Discussion

by Most.Kamrun Naher Shuchana 193-15-2926 - Saturday, 27 June 2020, 8:15 PM

f(x)=x-1/2

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In reply to Most.Kamrun Naher Shuchana 193-15-2926

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:44 AM

Correct!!!

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Re: Weekly Discussion

by Tamanna Akter (193-15-2937) - Saturday, 27 June 2020, 8:15 PM

Find the inverse function of f (x) = 2x+1

=(x-1)/2

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In reply to Tamanna Akter (193-15-2937)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:44 AM

Correct!!!

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Re: Weekly Discussion

by wasiul rashid (192-15-2869) - Saturday, 27 June 2020, 8:15 PM

(x-1)/2

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In reply to wasiul rashid (192-15-2869)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:44 AM

Correct!!!

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Re: Weekly Discussion

by abdullah al taky 193-15-2917 - Saturday, 27 June 2020, 8:15 PM

x-1/2

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In reply to abdullah al taky 193-15-2917

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by MD RAKIBUL ISLAM(193-15-3015) - Saturday, 27 June 2020, 8:15 PM

(x-1)/2

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In reply to MD RAKIBUL ISLAM(193-15-3015)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by Muhammad Shahedul Islam (193-15-2997) - Saturday, 27 June 2020, 8:15 PM

x-1/2

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In reply to Muhammad Shahedul Islam (193-15-2997)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by Sabrina Islam 193-15-2941 - Saturday, 27 June 2020, 8:15 PM

f(x) = 2x+1

sol: x-1/2

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In reply to Sabrina Islam 193-15-2941

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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In reply to First post

Re: Weekly Discussion

by Ata-E-Elahi 193-15-2946 - Saturday, 27 June 2020, 8:16 PM

The inverse function of f(x)=2x+1 is  (x-1)/2

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In reply to Ata-E-Elahi 193-15-2946

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by RIFAT ahmed (193-15-2911) - Saturday, 27 June 2020, 8:17 PM

(X-1)/2

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In reply to RIFAT ahmed (193-15-2911)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by Md.Atiqur Rahman - Saturday, 27 June 2020, 8:17 PM

(x-1)/2.

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In reply to Md.Atiqur Rahman

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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In reply to First post

Re: Weekly Discussion

by Razia Sultana Misu(193-15-2976) - Saturday, 27 June 2020, 8:17 PM

Ans : (x-1)/2

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In reply to Razia Sultana Misu(193-15-2976)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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In reply to First post

Re: Weekly Discussion

by Abdul Wahid 193-15-2992 - Saturday, 27 June 2020, 8:17 PM

(x-1)/2

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In reply to Abdul Wahid 193-15-2992

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by Md.Eamon Rahman (193-15-2967) - Saturday, 27 June 2020, 8:18 PM

Find the inverse function of f (x) = 2x+1

ans =(x-1)/2

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In reply to Md.Eamon Rahman (193-15-2967)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by MD Nahid Hasan 3006 - Saturday, 27 June 2020, 8:22 PM

(x-1)/2

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In reply to MD Nahid Hasan 3006

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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In reply to First post

Re: Weekly Discussion

by NUSRAT JAHAN (193-15-2924) - Saturday, 27 June 2020, 8:32 PM

x-1/2

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In reply to NUSRAT JAHAN (193-15-2924)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by Al-Ifran (193-15-2915) - Friday, 7 August 2020, 1:36 PM

sol: f(x)=x-1/2

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In reply to Al-Ifran (193-15-2915)

Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:43 AM

Correct!!!

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Re: Weekly Discussion

by Tania Khatun - Saturday, 15 August 2020, 8:42 AM

Let assume
y=f(x)
=>y=2x+1
=>y-1=2x
=>2x=y-1
=>x=(y-1)/2

So the inverse function of f(x) is (x-1)/2

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In reply to First post

Re: Weekly Discussion

by Faria Binta Kalam(193-15-2918) - Saturday, 22 August 2020, 7:50 PM

f(x)=x-1/2

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Re: Weekly Discussion

by Joshinta Jerin - Friday, 28 August 2020, 11:36 PM

f(x)=x-1/2

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