Weekly Discussion

Weekly Discussion

Number of replies: 43

Find the truth value for the following quantification where the domain consists of real numbers.

a) ∀x(x^2 ≥ x)

b) ∃x(x = 1)

In reply to First post

Re: Weekly Discussion

by abdullah al taky 193-15-2917 -
In reply to abdullah al taky 193-15-2917

Re: Weekly Discussion

by Tania Khatun -
2nd ans wrong.

Correct ans:
a) For real number if x=0.5 the x^2=0.25 in which 0.25<0.5. So for all real number 1st statement is not true. So, truth value of ∀x(x^2 ≥ x)=F
b) For all real number 1st statement is not true. So, truth value of ∃x(x = 1)=T
In reply to First post

Re: Weekly Discussion

by MD Nahid Hasan 3006 -
In reply to MD Nahid Hasan 3006

Re: Weekly Discussion

by Tania Khatun -
2nd ans wrong.

Correct ans:
a) For real number if x=0.5 the x^2=0.25 in which 0.25<0.5. So for all real number 1st statement is not true. So, truth value of ∀x(x^2 ≥ x)=F
b) For all real number 1st statement is not true. So, truth value of ∃x(x = 1)=T
In reply to First post

Re: Weekly Discussion

by Sabrina Islam 193-15-2941 -

a) false

b) false

In reply to Sabrina Islam 193-15-2941

Re: Weekly Discussion

by Tania Khatun -
2nd ans wrong.

Correct ans:
a) For real number if x=0.5 the x^2=0.25 in which 0.25<0.5. So for all real number 1st statement is not true. So, truth value of ∀x(x^2 ≥ x)=F
b) For all real number 1st statement is not true. So, truth value of ∃x(x = 1)=T
In reply to First post

Re: Weekly Discussion

by Al-Ifran (193-15-2915) -
In reply to Al-Ifran (193-15-2915)

Re: Weekly Discussion

by wasiul rashid (192-15-2869) -
In reply to wasiul rashid (192-15-2869)

Re: Weekly Discussion

by Tania Khatun -
2nd ans wrong.

Correct ans:
a) For real number if x=0.5 the x^2=0.25 in which 0.25<0.5. So for all real number 1st statement is not true. So, truth value of ∀x(x^2 ≥ x)=F
b) For all real number 1st statement is not true. So, truth value of ∃x(x = 1)=T
In reply to First post

Re: Weekly Discussion

by Faria Binta Kalam(193-15-2918) -
In reply to Faria Binta Kalam(193-15-2918)

Re: Weekly Discussion

by Tania Khatun -
2nd ans wrong.

Correct ans:
a) For real number if x=0.5 the x^2=0.25 in which 0.25<0.5. So for all real number 1st statement is not true. So, truth value of ∀x(x^2 ≥ x)=F
b) For all real number 1st statement is not true. So, truth value of ∃x(x = 1)=T
In reply to First post

Re: Weekly Discussion

by NUSRAT JAHAN (193-15-2924) -
In reply to NUSRAT JAHAN (193-15-2924)

Re: Weekly Discussion

by Tania Khatun -
2nd ans wrong.
Correct ans:
a) For real number if x=0.5 the x^2=0.25 in which 0.25<0.5. So for all real number 1st statement is not true. So, truth value of ∀x(x^2 ≥ x)=F
b) For all real number 1st statement is not true. So, truth value of ∃x(x = 1)=T
In reply to First post

Re: Weekly Discussion

by Tania Khatun -
a) For real number if x=0.5 the x^2=0.25 in which 0.25<0.5. So for all real number 1st statement is not true. So, truth value of ∀x(x^2 ≥ x)=F
b) For all real number 1st statement is not true. So, truth value of ∃x(x = 1)=T