Answer No.01

We know, SNR(dB)=10log(10) SP/NP

SNR(dB)=10log(10) 14/2

SNR(dB)=8dB

Answer No.02

We know,  SNR(dB)=10log(10) SNR

=> SNR=10xSNR(dB)/10

=> SNR=10x20/10

=> SNR=20

Now, 𝐶=3.32 B log 10 (1 +SNR)

C=3.32x12x(10)3xlog(10)(1+20)

C=52.68Kbit/sec