School Management

School Management

by Sajid Anowar -
Number of replies: 0

create database schoolmanagementsystem

use schoolmanagementsystem

create table Users

(

ID int primary key,

Username varchar(22) not null,

Password varchar(22) not null

);

 

create table Area

(

ID int primary key,

Name  varchar(25) not null

);

 

create table Subject

(

ID int primary key,

Name varchar(25) not null,

Abbreviation varchar(25) not null,

IDArea integer references Area(ID)

);

 

create table Level

(

ID integer primary key,

Name varchar(25) not null,

Principle varchar(25) not null

);

 

create table Grade

(

ID integer primary key IDENTITY,

Name varchar(25) not null,

IDLevel integer references Level(ID),

Observation int not null

);

 

create table StaffType

(

ID integer primary key,

Name varchar(25) not null

);

 

create table Staff

(

ID integer primary key,

IDStaffType int not null foreign key references StaffType(ID),

Name varchar(25) not null,

LastNameFather varchar(25) not null,

LastNameMother varchar(25) not null,

DateOfBirth varchar(25) not null,

PlaceOfBirth int not null,

Sex varchar(10) not null,

MobilePhone int not null,

Address varchar(30),

FatherName varchar(25) not null,

MotherName varchar(25) not null,

FatherContact int not null,

FatherPlaceOfWork varchar(30) not null,

MotherPlaceOfWork varchar(30) not null,

Salary int not null

);

 

create table GradeParalelo

(

ID integer primary key,

IDGrade integer references Grade(ID),

IDStaff integer references Staff(ID),

Name varchar(25) not null

);

 

create table Student

(

ID integer primary key,

IDGradeParalelo integer references GradeParalelo(ID),

Name varchar(25) not null,

FatherName varchar(25) not null,

MotherName varchar(25) not null,

DateOfBirth int not null,

PlaceOfBirth varchar(25) not null,

Sex varchar(25) not null,

MobilePhone int not null,

Address varchar(25) not null,

FatherMobilePhone int not null,

FatherProfession varchar(22) not null,                                                                                                                                    

MotherProfession varchar(22) not null,

);

 

create table Attendance

(

ID integer primary key,

IDStudent integer references Student(ID),

Attended int not null,

Date int not null

);

 

create table SubjectGrade

(

ID integer primary key,

IDGrade integer references Grade(ID),

IDSubject integer references Subject(ID)

);

 

create table ScoreRecord

(

ID integer primary key,

IDSubject integer references Subject(ID),

IDStudent integer references Student(ID),

FirstTrimester integer,

SecondTrimester integer,

ThirdTrimester integer,

FinalGrade integer,

Year int not null

);

--Show tables

select * from Users

select * from Area

select * from Subject

select * from Level

select * from Grade

select * from StaffType

select * from Staff

select * from GradeParalelo

select * from Student

select * from Attendance

select * from SubjectGrade

select * from ScoreRecord

--Alter table

alter table StaffType

add salaries decimal(8,2)

--Drop table

drop table Attendance

alter table StaffType drop column salaries

 

--DROP DATABASE command

drop database schoolmanagementsystem;

--Data Insert

Insert Into Users

values( 01,'Zubair', 4011),

(02,'Sam', '8011'),

(03, 'Zannat', '6011');

Insert Into Area

values( 01,'Zubair'),

(02,'Sam'),

(03, 'Zannat');

Insert Into Subject

values( 101,'Bangla','ban',01),

(103,'English','eng',02),

(107, 'Mathmatics', 'math',03);

Insert Into Level

values( 01,'Zubair','Senior teacher'),

( 02,'Sam','teacher'),

( 03,'Zannat','staff');

Insert Into StaffType

values( 01,'Zubair'),

(02,'Sam'),

(03, 'Zannat');

--Data show

select * from Users

--Where condition

select * from Area where ID=02

--Like operators

--Whose name start with a

select Name

from Area

where Name LIKE 'a%'

--Whose name end with a

select Name

from Area

where Name LIKE '%a'

--In any position a

select Name

from Area

where Name LIKE '%a%'

--2nd position a

select Name

from Area

where Name LIKE '_a%'

--In operator

select Name

from Subject

where Name IN ('Bangla');

 

--Between operator

--Find out the ID which in between 101 and 102

select ID

from Subject

where ID between 101 and 102

--Distinct

--Find unique information

select distinct(Name) from Subject

--Vaving clause

--Find out number of ID for each id where number of stuff should be less than 5

select count(distinct ID), ID

from Subject

group by ID

having count(distinct ID)<5

--Update value in table

update Subject set Name='Bengal' where ID=101

 

update Subject set Name='Math' where ID=103

 

--Drop table

drop table Subject

 

 

--Join

--Inner join

select Area.Name,

Area.Id,

Subject.Name,

Subject.ID from Area inner join Subject

on Area.ID=Suject.ID

 

--Left join

select Level.Name,

Level.ID,

Users.ID,

Users.ID from Level left join Users

on Level.ID=Users.ID

 

--Right join

select Staff.Name,

Staff.ID,

Level.ID,

Level.Name

from Staff right join Level

on Staff.ID=eLevel.Name

 

--Full outer join

select Subject.Name,

Subject.ID,

Area.ID,

Area.ID from Subject full join Area

on Subject.ID=Area.ID

 

 

--Experiment 4 create and drop views

create view Addresses as select Name,Abbreviation

from Subject where ID=103;

drop view Addresses;

 

--Use stored procedure

create procedure ID as

select * from

Subject, Area

go;

exec ID;